Как вы делите (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?

Как вы делите (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?
Anonim

Ответ:

#color (синий) ((- 6х ^ 4-3x ^ 3-2x ^ 2-4x-7) / (х ^ 2 + 3) = - 6х ^ 2-3x + 16 + (5x-55) / (х ^ 2 + 3)) #

Объяснение:

# (- 6х ^ 4-3x ^ 3-2x ^ 2-4x-7) / (х ^ 2 + 3) #

Метод длинного деления:

# "" "" "" "" "" "" подчеркивание (-6x ^ 2-3x + 16 "" "" "" "" "" "" "" "" "") #

# Х ^ 2 + 0 * х + 3 | ~ -6x ^ 4-3x ^ 3-2x ^ 2-4x-7 #

# "" "" "" "" "" "" подчеркивание (-6x ^ 4 + 0 * x ^ 3-18x ^ 2 "" "" "") # #

# "" "" "" "" "" "" "" "" "-3x ^ 3 + 16x ^ 2-4x-7 #

# "" "" "" "" "" "" "" "" "подчеркивание (-3x ^ 3 + 0 * x ^ 2-9x) #

# "" "" "" "" "" "" "" "" "" "" "16x ^ 2 + 5x-7 #

# "" "" "" "" "" "" "" "" "" "" "подчеркивание (16x ^ 2 + 0 * x + 48) #

# "" "" "" "" "" "" "" "" "" "" "" "" "+ 5x-55 larr #остаток

Ответ

#color (синий) ((- 6х ^ 4-3x ^ 3-2x ^ 2-4x-7) / (х ^ 2 + 3) = - 6х ^ 2-3x + 16 + (5x-55) / (х ^ 2 + 3)) #